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However you use double square brackets and the formulas are set up like this
[math] (remember the double square brackets though)
\dfrac {3x^3-4x^2+3x-4} {x^4-2x^2+5}
[math]
gives
[math]
area=\pi r^2
[math]
gives
[math]
\sqrt {\frac {1}{3x} y^5-3}
[math]
gives
[math]
\left[ \dfrac {1}{3x} y^5-3 \right]
[math]
gives
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However you use double square brackets and the formulas are set up like this
[math] (remember the double square brackets though)
\dfrac {3x^3-4x^2+3x-4} {x^4-2x^2+5}
[math]
gives
[math]
area=\pi r^2
[math]
gives
[math]
\sqrt {\frac {1}{3x} y^5-3}
[math]
gives
[math]
\left[ \dfrac {1}{3x} y^5-3 \right]
[math]
gives